I am trying to validate a text string as a date before processing it, however both of the regex i have tried are throwing syntax errors and I can't see why. From what I can tell there is nothing wrong with either. These are the strings:
var datePattern1 = new RegExp( (0[1-9]|1[012])[-](0[1-9]|[12][0-9]|3[01])[-](19|20)\d\d );
and
var datePattern2 = new RegExp( [0-3][0-9]-(0|1)[0-9]-(19|20)[0-9]{2} );
Appreciate any help.
From stackoverflow
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You are missing the quotes around your expressions:
var datePattern1 = new RegExp( "(0[1-9]|1[012])[-](0[1-9]|[12][0-9]|3[01])[-](19|20)\d\d" ); var datePattern2 = new RegExp( "[0-3][0-9]-(0|1)[0-9]-(19|20)[0-9]{2}" );MalcomTucker : is it really as simple as that? dohGuffa : No, it's not that simple. Also the \d\d at the end has to be \\d\\d. -
Either pass a string to the
RegExpconstructor as darin mentioned or use the RegExp syntax “/ … /”:var datePattern1 = /(0[1-9]|1[012])[-](0[1-9]|[12][0-9]|3[01])[-](19|20)\d\d/; var datePattern2 = /[0-3][0-9]-(0|1)[0-9]-(19|20)[0-9]{2}/; -
The Regexp() constructor expects a string, so you need to quote your regex:
var datePattern2 = new RegExp('[0-3][0-9]-(0|1)[0-9]-(19|20)[0-9]{2}');When using double quotes, watch out for backslash escapes in the regex. Alternatively, you can use the Perl syntax:
var datePattern2 = /[0-3][0-9]-(0|1)[0-9]-(19|20)[0-9]{2}/;MalcomTucker : if you use the perl syntax do you then pass the var to the regex constructor?Rob Kennedy : No. The slash syntax is a "regex literal." No need to create a Regex object around it.
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