I have a dict where each key references an int value. What's the best way to sort the keys into a list depending on the values?
From stackoverflow
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>>> mydict = {'a':1,'b':3,'c':2} >>> sorted(mydict, key=lambda key: mydict[key]) ['a', 'c', 'b']MizardX : thanks, Brian R. Body. :)MizardX : Bondy* ... can't spell tody -
list = sorted(dict.items(), key=lambda x: x[1]) -
[v[0] for v in sorted(foo.items(), key=lambda(k,v): (v,k))] -
I like this one:
sorted(d, key=d.get)Kiv : This is really the most elegant.Richard J. Terrell : Too bad I haven't waited with the accept. +1 -
odict might work for you.
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